The value of x in the given expression can be either -41 or 45. The correct option is B.
<h3>What is Absolute Value?</h3>
An absolute value of |x| {modulus of x} is the value of a real number x, the value we get is always a non-negative number, for example, |-5| will give 5, and also, |5| will give 5 as well.
Given the modulus function (1/5)|x - 4| - 3 = 6. Now, there will be two cases of this because the value of x can be either negative, x<0 or it can positive, x>0. Therefore, the given modulus function can be solved as shown below.
(1/5)(x-4) - 3 = 6
(x/5) - (4/5) - 3 = 6
(x - 4 - 15)/5 = 6
x - 4 -15 = 30
x = 30 + 15 + 4
x = 45
(1/5)(-x+4) - 3 = 6
(-x/5) + (4/5) - 3 = 6
(- x + 4 - 15)/5 = 6
- x + 4 -15 = 30
-x = 30 + 15 - 4
-x = 41
x = -41
Hence, the value of x in the given expression can be either -41 or 45.
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Use ac method
for ax²+bx+c=0 when a≠1
multiply a and c, let's call the product r
what 2 numbesr multiply to get r and add to get b
2y²+9y+9=0
2*9=18
wat 2 numbers multiply to get 18 and add to get 9
3 and 6
split it up to that
2y²+3y+6y+9=0
group
(2y²+3y)+(6y+9)=0
factor
y(2y+3)+3(2y+3)=0
undistribute
(y+3)(2y+3)=0
set to zero
y+3=0
y=-3
2y+3=0
2y=-3
y=-3/2
y=-3 and -3/2
it's factored form is (x+3)(2x+3)
Answer:
Diameter: 4
Radius: 2
Equation: ( x-3 ) + ( y + 2) = 4
Answer:
K
Step-by-step explanation:
techincally, I don't know if I am right, but there is more than one answer. The boundries/restrictions of what length DF could be are 2.477 < x < 8.477
<h3>Point Y is the midpoint of segment XZ. Then value of x is 20</h3>
<em><u>Solution:</u></em>
Given that,
<em><u>Point Y is the midpoint of segment XZ</u></em>
XY = 2(3x +1)
YZ = 5x + 22
To find: Value of x
Since, Point Y is the midpoint of segment XZ,
Therefore,
XY = YZ
2(3x + 1) = 5x + 22
6x + 2 = 5x + 22
6x - 5x = 22 - 2
<h3>x = 20</h3>
Thus, value of x is 20