Know the order of operations. However, one of the trickiest things about solving an algebra<span> equation as a beginner is knowing where to start. Luckily, there's a specific order for solving these problems: first </span>do<span> any math operations in parentheses, then </span>do<span> exponents, then multiply, then divide, then add, and finally subtract</span>
The regular octagon has eight equal sides. Then the area of the regular octagon of side length be 4.6 is 102 ft².
<h3>What is a regular octagon?</h3>
It is a polygon that has eight equal sides. In a regular octagon, the opposite sides are parallel. And its diagonals are also equal and intersect at mid-point.
Given
A regular octagon has a radius of 6 ft and a side length of 4.6 ft.
We know the formula for the regular octagon.
Area of the regular octagon = 2(1 + ) a²
Where a be the side of a regular octagon.
Then the area of the regular octagon will be.
Thus, the area of the regular octagon of side length be 4.6 is 102 ft².
More about the regular octagon link is given below.
brainly.com/question/858868
Answer:
A
Step-by-step explanation:
Given
y - 2x - 8 = 0 ( add 2x + 8 to both sides )
y = 2x + 8 → (1)
y² + 8x = 0 → (2)
Substitute y = 2x + 8 into (2)
(2x + 8)² + 8x = 0 ← expand left side using FOIL and simplify
4x² + 32x + 64 + 8x = 0
4x² + 40x + 64 = 0 ( divide through by 4 )
x² + 10x + 16 = 0 ← in standard form
(x + 8)(x + 2) = 0 ← in factored form
x + 8 = 0 ⇒ x = - 8
x + 2 = 0 ⇒ x = - 2
Substitute these values into (1) for corresponding values of y
x = - 8 : y = 2(- 8) + 8 = - 16 + 8 = - 8 ⇒ P (- 8, - 8)
x = - 2 : y = 2(- 2) + 8 = - 4 + 8 = 4 ⇒ Q (- 2, 4 )
Calculate the length of PQ using the distance formula
PQ =
with (x₁, y₁ ) = P (- 8, - 8) and (x₂, y₂ ) = Q (- 2, 4 )
PQ =
=
=
=
=
=
= ×
= 6 → A