An outfielder throws a 1.1 kg baseball at a speed of 62 m/s and an initial angle of 12.3 ◦ . What is the kinetic energy of the b
1 answer:
Answer:
= 2,018.3 J
Explanation:
mass (m) = 1.1 kg
velocity (v) = 62 m/s
initial angle(θ) = 12.3°
kinetic energy =
where
- m is the mass
- v is the velocity, which has two components
v = Vx + Vy (horizontal component + vertical component)
at the maximum height, velocity is 0, so Vy = 0 and v= Vx
v = Vx = v.cosθ
v = 62 x cos 12.3 = 60.6 m/s
therefore kinetic energy = =
= 2,018.3 J
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Answer:
a) b) d)
Explanation:
The question is incomplete. The Complete question might be
In an inertial frame of reference, a series of experiments is conducted. In each experiment, two or three forces are applied to an object. The magnitudes of these forces are given. No other forces are acting on the object. In which cases may the object possibly remain at rest? The forces applied are as follows: Check all that apply.
a)2 N; 2 N
b) 200 N; 200 N
c) 200 N; 201 N
d) 2 N; 2 N; 4 N
e) 2 N; 2 N; 2 N
f) 2 N; 2 N; 3 N
g) 2 N; 2 N; 5 N
h ) 200 N; 200 N; 5 N
For th object to remain at rest, sum of all forces must be equal to zero. Use minus sign to show opposing forces
a) 2+(-2)=0 here minus sign is to show the opposing firection of force
b) 200+(-200)=0
c) 200+(-201)0
d) 2+2+(-4)=0
e) 2+2+(-2)0
f) 2+2+(-3) 0; 2+(-2)+3
0
g) 2+2+(-5)0; 2+(-2)+5
0
h)200 + 200 +(-5)0; 200+(-200)+5
0
The butterfly takes a vertical perpendicular path equivalent to 9m and travels a horizontal distance of 17m. The net path between the two is equivalent to that of the hypotenuse, so we will apply the Pythagorean theorem.
Therefore the magnitude of the butterfly's displacement is 9m
