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2 years ago

7. Find two consecutive even integers such that twice the smaller is

Mathematics

1 answer:

Arturiano [62]2 years ago

7 0

Answer:

Step-by-step explanation:

The difference between two consecutive even integers is 2

and even integer is always twice some integer

So:

2x ← smaller of numbers

2x+2 ← larger of numbers

2×2x ← twice the smaller of numbers

3(2x+2) ← three times the larger

3(2x+2)-26 ← 26 less than 3 times the larger

twice the smaller is 26 less than 3 times the larger:

3(2x+2) - 26 = 2×2x

6x + 6 - 26 = 4x

+20 +20

6x - 4x = 20

2x = 20

2x+2 = 20 + 2 = 22

Check: 2×20=40; 40+26 = 66; 66÷3=22

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Scorpion4ik [409]

SOLUTION:

Step 1:

In this question, we are given the following:

Step 2:

The details of the solution are as follows:

What variable expression should you subtract from both sides of the equation so that you are left with no variables on the right-hand side?

The variable expression is: subtract 5x from both sides so that you are left with no variables on the right-hand side

$\begin{gathered} 6x\text{ - 10 = 5x + 15} \\ \text{Subtract 5 x from both sides, we have that:} \\ 6x\text{ - 5x - 10 = 5x - 5x + 15} \\ x\text{ - 10 = 15} \\ \text{Now, add 10 to both sides, we have that:} \\ x\text{ - 10 + 10 = 15 + 10} \\ x\text{ = 25} \\ \text{check:} \\ 6x\text{ - 10 = 5x + 15} \\ \sin ce,\text{ x = 25 , we have that:} \\ 6(25)\text{ - 10 = 5(25) + 15 } \\ 150\text{ - 10 = 125+ 15= 140 ( COR}\R ECT) \end{gathered}$

CONCLUSION:

The final answer is: