Answer:
1. The current will drop to half of its original value.
Explanation:
The problem can be solved by using Ohm's law:
where
V is the voltage across the circuit
R is the resistance of the circuit
I is the current
We can rewrite it as
In this problem, we have:
- the resistance of the circuit remains the same: R' = R
- the voltage is decreased to half of its original value:
So, the new current will be
so, the current will drop to half of its original value.
Answer
given,
firm is producing = 2,475 units
output by hiring 50 workers W = $20 per hour
25 units of capital R = $10 per hour
marginal product of labor = 40
marginal product of capital = 25
Firm is not minimizing the cost because the firm use more capital and less labor.
Answer:
The gravitational force between m₁ and m₂, is approximately 1.06789 × 10⁻⁶ N
Explanation:
The details of the given masses having gravitational attractive force between them are;
m₁ = 20 kg, r₁ = 10 cm = 0.1 m, m₂ = 50 kg, and r₂ = 15 cm = 0.15 m
The gravitational force between m₁ and m₂ is given by Newton's Law of gravitation as follows;
Where;
F = The gravitational force between m₁ and m₂
G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²
r₂ = 0.1 m + 0.15 m = 0.25 m
Therefore, we have;
The gravitational force between m₁ and m₂, F ≈ 1.06789 × 10⁻⁶ N
-6.98 × 10-^7 is the answer <3