The correct answer is 9.4897 mL
It is necessary to understand a substance's mass, volume, and density in order to answer this question. By dividing a material's mass by volume, the density of the substance may be calculated. The equation for density may now be written in mathematical form using the expression for density, and the equation for mass can be produced by rearrangement using the equation for density as a starting point.
Mass of acetone = 7.44 g (given)
Volume of acetone (v) = mass of acetone ÷ density of acetone
V = 7.44 g ÷ 0.784 g/mL
V = 9.4897 mL
Hence volume of acetone = 9.4897 mL
To learn more about density refer the link:
brainly.com/question/6107689
#SPJ9
C distillation you would evaporate the water into another container leaving you with the salt free water
Wait what
What
Huh
Kinda confused
Given data:
Volume of HCl = 14.22 ml
Molarity of HCl = 2.97 M
mmoles of HCl = 14.22 * 2.97 = 42.2 mmoles
Volume of NaOH = 5.00 ml
Molarity of NaOH = 0.1055 M
mmoles of NaOH = 5.00 *.1055 = 0.5275 mmoles
Since HCl and NaOH combine in a 1:1 ratio
# moles of NaOH = # moles of excess HCl that is neutralized = 0.5275 moles
Now, the total moles of HCl taken = # mmoles HCl neutralized by antacid + # mmoles of excess HCl
42.2 = mmoles HCl neutralized by antacid + 0.5275
Therefore,
mmoles of HCl neutralized by antacid = 42.2 - 0.5275 = 41.6725 mmoles = 41.7 mmoles
Primary alkyl halides tend to undergo the SN2 reaction mechanism in nucleophilic substitution since there is less steric hindrance for nucleophilic attack and the carbocations that they form are not as stable as those formed from tertiary alkyl halides.
1-bromopentane > 1-bromo 2-methylbutane > <span>1-bromo-3-methylbutane</span>> 2-bromo 2-methylbutane
