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2 years ago

What is the product of (2x2 + 5x - 3) and (3x +7)?

Mathematics

1 answer:

kicyunya [14]2 years ago

8 0

Answer:

6x^3 + 29x^2 + 26x -21

Step-by-step explanation:

(2x^2 + 5x -3)(3x + 7) = 6x^3 + 14x^2 + 15x^2 + 35x - 9x -21

= 6x^3 + 29x^2 + 26x -21

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Type the correct answer for each.

xxTIMURxx [149]

If point $\left(x,\ \frac{\sqrt{7}}{3}\right)$ is on the unit ircle, then:

$x^2+\left( \frac{ \sqrt{7} }{3} \right)^2=1 \\ \\ \Rightarrow x^2+ \frac{7}{9} =1 \\ \\ \Rightarrow x^2=1- \frac{7}{9} = \frac{2}{9} \\ \\ \Rightarrow x= \sqrt{ \frac{2}{9} } = \frac{ \sqrt{2} }{3}$

Since, the point is in the second quadrant, x is negative.

Thus, $(x,\ y)=\left(x,\ \frac{\sqrt{7}}{3}\right)=\left(-\frac{ \sqrt{2} }{3},\ \frac{\sqrt{7}}{3}\right)$

Part A:

$3 \sqrt{7} =6\left( \frac{ \sqrt{7} }{2} \right) \\ \\ =6\left( \frac{ \sqrt{7} }{3} \cdot \frac{3}{ \sqrt{2} } \right) \\ \\ =6\left( \frac{ \frac{ \sqrt{7} }{3} }{ \frac{ \sqrt{2} }{3} } \right)=-6\left( \frac{ \frac{ \sqrt{7} }{3} }{ -\frac{ \sqrt{2} }{3} } \right) \\ \\ =-6\left( \frac{y}{x} \right)=-6\tan\theta$

Therefore, $-6\tan\theta=3\sqrt{7}$ .

Part B:

$- \frac{ \sqrt{7} }{2} =- \frac{ \sqrt{7} }{3} \cdot \frac{3}{ \sqrt{2} } \\ \\ =- \frac{ \frac{ \sqrt{7} }{3} }{ \frac{ \sqrt{2} }{3} } = \frac{ \frac{ \sqrt{7} }{3} }{ -\frac{ \sqrt{2} }{3} } = \frac{y}{x} \\ \\ =\tan\theta$

Therefore, $\tan\theta=- \frac{ \sqrt{7} }{2}$

8 0

2 years ago

) Samantha has 6/7 of a apple pie. Drayden has 3/7 of a apple pie. How much pie do they have altogether? (Make sure to simply if

slavikrds [6]

Answer: 1 2/7, 7/9,3/4

Step-by-step explanation: 9/7 you had to make a whole then make the fraction 2/7. 7/9 you literally just had to subtract 8-1 to gt 7 and because the denominator didn't need to change it so that makes it 7/9. And the last one 9/12 well 3 can go into 9 and 12 evenly. For 9 it goes in 3 times and for 12 it goes in 3 to any you get 3/4.

4 0

2 years ago

Qual é a diferença entre a população de Toledo e Umuarama?

Inessa05 [86]

E preciso subtrair.

119207
- 100716
----------------
18491

3 0

2 years ago

Please help, this will just take a minute of your time ❤︎ (literally)<br>(Discriminant Worksheet)

igomit [66]

Answer:

$\large\boxed{x=-\dfrac{7-\sqrt{97}}{4}\ \vee\ x=-\dfrac{7+\sqrt{97}}{4}}$

Step-by-step explanation:

$ax^2+bx+c=0\\\\\Delta=b^2-4ac\\\\\text{if}\ \Delta0,\ \text{then an equation has two solutions:}\ x=\dfrac{-b\pm\sqrt\Delta}{2a}\\\\\text{We have:}\\\\-2x^2-7x+10=4\qquad\text{subtract 4 from both sides}\\\\-2x^2-7x+6=0$

$a=-2,\ b=-7,\ c=6\\\\\Delta=(-7)^2-4(-2)(6)=49+48=97>0\\\\\sqrt\Delta=\sqrt{97}\\\\x=\dfrac{-(-7)\pm\sqrt{97}}{2(-2)}=\dfrac{7\pm\sqrt{97}}{-4}=-\dfrac{7\pm\sqrt{97}}{4}$

6 0

2 years ago

5h+6y+4h+9y=3h+5y6h+9y

Leokris [45]

H=6y/5y^(6) -6

hope this helps!!!!!!!!

3 0

2 years ago