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2 years ago

Why is water necessary for living organisms?

2 answers:

7 0

I believe the correct answer from the choices listed above is the third option. Water is necessary for living organisms because all <span>organisms need water to transport chemicals into their cells. Hope this answers the question. Have a nice day.</span>

Finger [1]2 years ago

3 0

The answer is: All organisms need water to transport chemicals into their cells.

For example, supplies the body with oxygen and nutrients, and picks up carbon dioxide wastes.

The blood transports:

1) oxygen from the lungs to the cells of the body.

2) carbon(IV) oxide from metabolism to the lungs, where it is exhaled.

3) nutrients, transports hormones and removes waste products.

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5. Didderent betwen group and period.

Ronch [10]

A group goes vertically and a period goes horizontally.

(a group goes down and a period goes across)

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2 years ago

An empty graduated cylinder weighs 26.5 grams and when it is filled with an unknown liquid to the 45.8 ml mark the cylinder and

Softa [21]

Answer:

24.2 is the density of the liquid

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2 years ago

A friend tells you he read on a web site that earth is getting smaller, What can you tell him that shows Earth's size is not cha

Lyrx [107]

U can show him that Earth isn't getting smaller, because things WOULD be getting smaller, and our houses would be getting smaller, IF everything shrunk WITH Earth.

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2 years ago

Assume that a daily diet of 2000 calories (i.e. 8.37 x 106 J) is converted completely to body heat.

slava [35]

Answer:

(a) the mass of the water is 3704 g

(b) the mass of the water is 199, 285.7 g

Explanation:

Given;

Quantity of heat, H= 8.37 x 10⁶ J

Part (a) mass of water (as sweat) need to evaporate to cool that person off

Latent heat of vaporization of water, Lvap. = 2.26 x 10⁶ J/kg

H = m x Lvap.

$m = \frac{H}{L._{vap}} =\frac{8.37 * 10^6.J}{2.26*10^6\ \frac{J}{kg}} = 3.704 \ kg$

mass in gram ⇒ 3.704 kg x 1000g = 3704 g

Part (b) quantity of water raised from 25.0 °C to 35.0 °C by 8.37 x 10⁶ J

specific heat capacity of water, C, 4200 J/kg.°C

H = mcΔθ

where;

Δθ is the change in temperature = 35 - 25 = 10°C

$m =\frac{H}{c* \delta \theta} = \frac{8.37 *10^6}{4200*10} = 199.2857 kg$

mass in gram ⇒ 199.2857 kg x 1000 g = 199285.7 g

5 0

2 years ago

Pls just help me out the vid is 6 Chemical Reactions That Changed History; need help on no.6. I DON’T EVEN KNOW HOW TO SOLVE IT

GREYUIT [131]

Explanation:

HCL you can do it yourself .try again

4 0

2 years ago