Let us formulate the independent equation that represents the problem. We let x be the cost for adult tickets and y be the cost for children tickets. All of the sales should equal to $20. Since each adult costs $4 and each child costs $2, the equation should be
4x + 2y = 20
There are two unknown but only one independent equation. We cannot solve an exact solution for this. One way to solve this is to state all the possibilities. Let's start by assigning values of x. The least value of x possible is 0. This is when no adults but only children bought the tickets.
When x=0,
4(0) + 2y = 20
y = 10
When x=1,
4(1) + 2y = 20
y = 8
When x=2,
4(2) + 2y = 20
y = 6
When x=3,
4(3) + 2y= 20
y = 4
When x = 4,
4(4) + 2y = 20
y = 2
When x = 5,
4(5) + 2y = 20
y = 0
When x = 6,
4(6) + 2y = 20
y = -2
A negative value for y is impossible. Therefore, the list of possible combination ends at x =5. To summarize, the combinations of adults and children tickets sold is tabulated below:
Number of adult tickets Number of children tickets
0 10
1 8
2 6
3 4
4 2
5 0
Answer:
width = 10 inches
Step-by-step explanation:
V = lwh
w = = = = 10 inches
7x + 2y = 2
2x - y = 10
2y = - 7x + 2
- y = - 2x + 10
2y = -7x + 2
y = 2x - 10
y= 2x - 10
y = -3.5x + 1
y = 2x - 10
Now, let's find "x" first by doing a substituion !
2x - 10 = - 3.5x + 1
y = 2x - 10
2x + 3.5x = 1 + 10
y = 2x - 10
5.5x = 11
y= 2x - 10
y= 2*2 - 10 = 4 - 10 = -6
In short, the answer would be : y = -6 (Option B).Hope this helps !
Photon
Answer:
Step-by-step explanation:
The question should be :
A solid right pyramid has a square base with an edge length of s units and a height of h units.
The formula for the volume of the pyramid is given by :
A is area of base and h is height.
As edge length is s units.
A = (s)²
So,
So, the required volume is one-thirds s²h unit³.
Answer:
2/6 times
Step-by-step explanation:
only side 5 and 6 are greater than four and with fair rolls you would expect the die to land on each side once. So 2/6 times you would expect a roll greater than 4.