B. 10, 5, 2.5, 1.25, 0.625, 0.3125
Answer:
4c + 15
Step-by-step explanation:
THIS IS THE COMPLETE QUESTION BELOW;
A department store's customer parking lot has 4 rows with an equal number of parking spots in each row. The lot also has 15 parking spots for store employees. If c cars can be parked in each of the 4 main rows of the parking lot, what is the expression for the maximum number of cars that can be parked in the parking lot?
15c − 4
c(15 − 4)
4c + 15
4(c + 15)
✓We were told that the customer stores parking has Total number of 4 rows,
✓ for " c" cars to be parked in the 4 main rows i.e in each of them, we can calculate the overall numbers of car parked in the rolls as ( 4 × c)= 4c
✓ we were told that there are 15 parking spots available to employees in the store
✓ maximum number of cars that can fit into the parking lot will be ( 15 + 4c)
= 4c + 15
682 divide by 4 = 170.5
is that right no or yes
Answer:
The answer would be $5.5
Step-by-step explanation:
First, multiply $0.12 by 25 to get $3. Add the $3 to $2.50 to get your answer of $5.5
Area of the trapezium = 1/2 (40 + 160) x 70
Area of the trapezium = 7000 ft²
One bag of fertilizer = 4000 ft²
Number of bags of fertilizer needed = 7000 ÷ 4000 = 1.75 bags.
Since only full bags of fertilizer can be bought, 2 bags of fertilizer are needed.
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Answer: 2 bags of fertilizer
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