Answer:
<h2>$ 22200 in higher yielding bank and $ 44400 in lower yielding bank</h2>
Step-by-step explanation:
Jolene invests in two bank accounts. The first account gives a 4% interest per year and the second bank gives a 10% interest rate per year.
She puts twice as much in the lower yielding bank account. Let us denote the amount put in high yielding bank account by . Lower yielding bank account will have .
Interest from lower yielding bank =
Interest from higher yielding bank =
Total Interest per year = $ 3996 =
∴ Jolene invested $ 22200 in higher yielding bank and $ 44400 in lower yielding bank.
Hey there!
The number of equal parts that something is evenly distributed into is the <u>divisor.</u>
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<em>Hope this helps!</em>
Answer:
a = 1, b = 2, c = 3
Step-by-step explanation:
I know of two ways to solve quadratic equations. The first is through factoring. Let us take the example (x^2)+2x+1=0. We can factor this equation out and the factors would be (x+1)(x+1)=0. To solve for the roots, we equate each factor to 0, that is
x+1=0; x+1=0
In this case, the factors are the same so the root of the equation is
x=1.
The other way is to use the quadratic formula. The quadratic formula is given as [-b(+-)sqrt(b^2-4ac)]/2a where, using our sample equation above, a=1, b=2 and c=1. Substitute these to the formula, and you will get the same answer as the method above.
Answer:
The number of once is 9.1
The number of hundreds is 8.9
Step-by-step explanation:
Given as :
The total of digits having ones and hundreds = 900
The sum of digits = 18
Let The number of ones digit = O
And The number of hundreds digit = H
So, According to question
H + O = 18 .........1
100 × H + 1 × O = 900 ........2
Solving the equation
( 100 × H - H ) + ( O - O ) = 900 - 18
Or, 99 H + 0 = 882
Or , 99 H = 882
∴ H =
I.e H = 8.9
Put the value of H in eq 1
So, O = 18 - H
I.e O = 18 - 8.9
∴ O = 9.1
So, number of once = 9.1
number of hundreds = 8.9
Hence The number of once is 9.1 and The number of hundreds is 8.9
Answer