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2 years ago

9

When x = 12, find the ordered-pair solution of y = −(1/6)x − 2

1 answer:

Juliette [100K]2 years ago

7 0

Y = -(1/6)(12) - 2 = -2 - 2 = -4
Therefore, solution is (12, -4)

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A freezer is shaped like a rectangular prism. It has a length of 8 feet and a height of 3 feet. The volume is 54 cubic feet. Fin

yarga [219]

Well the formula:

V = Bh
54= 3*w*8
54= 24w
24w=54
w= 54/24
w= 2.25

4 0

2 years ago

Can someone please explain how to do number 9.

bogdanovich [222]

Answer:

x<15, probably

Step-by-step explanation:

maybe multiply 2 to each side to eliminate the fraction. so 3x+15<60. subtract 15 to isolate the variable term so 3x<45. divide by 3 to isolate x so x<15. check the work. is the inequality true for all values of x less than 15? let's try the first possible integer value, 14, to be sure. 3(14)+15= 57. so 57/2<30. now 57/2 is 28.5 and 28.5<30 so it seems right

7 0

2 years ago

A clothing manufacturer uses the model a=f+4−−−−√−36−f−−−−−√ to estimate the amount of fabric to order from a mill. In the formu

Anit [1.1K]

Questions:

A clothing manufacturer uses the model a = √(f + 4) - √(36 - f) to estimate the amount of fabric to order from a mill. In the formula, a is the number of apparel items (in hundreds) and f is the number of units of fabric needed. If 400 apparel items will be manufactured , how many units of fabric should be ordered?

Answer:

32 units of fabrics

Step-by-step explanation:

Given

$a = \sqrt{f + 4} - \sqrt{36 - f}$

Required

Find f when a = 4

Substitute 4 for a

$4 = \sqrt{f + 4} - \sqrt{36 - f}$

Rewrite as:

$\sqrt{36 - f} + 4 = \sqrt{f + 4}$

Square both sides

$(\sqrt{36 - f} + 4)^2 = (\sqrt{f + 4})^2$

$(\sqrt{36 - f} + 4)^2 = f + 4$

$36 - f + 8\sqrt{36 - f} + 16 = f + 4$

Collect Like Terms

$8\sqrt{36 - f}= f +f+ 4 - 36 -16$

$8\sqrt{36 - f}= 2f -48$

Divide through by 2

$4\sqrt{36 - f}= f -24$

Square both sides

$16(36-f) = (f - 24)^2$

$16(36-f) = f^2 - 48f + 576$

$576-16f = f^2 - 48f + 576$

$-16f = f^2 - 48f$

Collect like terms

$f^2 - 48f + 16f = 0$

$f^2 -32f = 0$

Factorize

$f(f - 32) = 0$

$f = 0$ or $f = 32$

f can not be 0 because some units must be ordered.

So, f = 32

6 0

2 years ago

PLEASE HELP ASAP!! <br> Please its due in 5 min!

-Dominant- [34]

Answer:

first question) m = - 63
second question) y = 4

sorry if this is late, hope this helped!

5 0

1 year ago

On a coordinate plane, the segment with endpoints (10, 40) and (70, 120) is

OlgaM077 [116]

Answer:

The length of the resulting segment is 500.

Step-by-step explanation:

Vectorially speaking, the dilation is defined by following operation:

$P'(x,y) = O(x,y) + k\cdot [P(x,y)-O(x,y)]$ (1)

Where:

$O(x,y)$ - Center of dilation.

$P(x,y)$ - Original point.

$k$ - Scale factor.

$P'(x,y)$ - Dilated point.

First, we proceed to determine the coordinates of the dilated segment:

( $P(x,y) = (10, 40)$ , $Q(x,y) = (70, 120)$ , $O(x,y) = (0,0)$ , $k = 5$ )

$P'(x,y) = O(x,y) + k\cdot [P(x,y)-O(x,y)]$

$P(x,y) = (0,0) +5\cdot [(10,40)-(0,0)]$

$P'(x,y) = (50,200)$

$Q'(x,y) = O(x,y) + k\cdot [Q(x,y)-O(x,y)]$

$Q' (x,y) = (0,0) +5\cdot [(70,120)-(0,0)]$

$Q'(x,y) = (350, 600)$

Then, the length of the resulting segment is determined by following Pythagorean identity:

$l_{P'Q'} = \sqrt{(350-50)^{2}+(600-200)^{2}}$

$l_{P'Q'} = 500$

The length of the resulting segment is 500.

3 0

2 years ago