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2 years ago

joe correctly answered 70% of the questions on a test. there were 50 questions. how many questions did joe answer correctly?

2 answers:

8 0

Your answer is 35 because you do 35 divided by 50 which equals 0.7 starting from the decimal, move two spaces to the right and you will get 70%

PolarNik [594]2 years ago

6 0

.70 *50 =35 .......

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Please help me with the below question.

VMariaS [17]

By letting

$y = \displaystyle \sum_{n=0}^\infty c_n x^{n+r}$

we get derivatives

$y' = \displaystyle \sum_{n=0}^\infty (n+r) c_n x^{n+r-1}$

$y'' = \displaystyle \sum_{n=0}^\infty (n+r) (n+r-1) c_n x^{n+r-2}$

a) Substitute these into the differential equation. After a lot of simplification, the equation reduces to

$5r(r-1) c_0 x^{r-1} + \displaystyle \sum_{n=1}^\infty \bigg( (n+r+1) c_n + (n + r + 1) (5n + 5r + 1) c_{n+1} \bigg) x^{n+r} = 0$

Examine the lowest degree term $\left(x^{r-1}\right)$ , which gives rise to the indicial equation,

$5r (r - 1) + r = 0 \implies 5r^2 - 4r = r (5r - 4) = 0$

with roots at r = 0 and r = 4/5.

b) The recurrence for the coefficients $c_k$ is

$(k+r+1) c_k + (k + r + 1) (5k + 5r + 1) c_{k+1} = 0 \implies c_{k+1} = -\dfrac{c_k}{5k+5r+1}$

so that with r = 4/5, the coefficients are governed by

$c_{k+1} = -\dfrac{c_k}{5k+5} \implies \boxed{g(k) = -\dfrac1{5k+5}}$

c) Starting with $c_0=1$ , we find

$c_1 = -\dfrac{c_0}5 = -\dfrac15$

$c_2 = -\dfrac{c_1}{10} = \dfrac1{50}$

so that the first three terms of the solution are

$\displaystyle \sum_{n=0}^2 c_n x^{n + 4/5} = \boxed{x^{4/5} - \dfrac15 x^{9/5} + \frac1{50} x^{13/5}}$

4 0

1 year ago

Write an algebraic expression with the variable x that has a value of 3 when evaluated

kari74 [83]

X=23

(x+5) - 25 = 3?

If this is what you mean.

7 0

2 years ago

9 of 10

Aleks04 [339]

$\frac{3}{10}$

Answer:

Step-by-step explanation:

I just pressed 27/90 on the calculator hahahha

6 0

2 years ago

Read 2 more answers

After he finished breakfast, Mr. Edwards left for work at fifteen minutes after seven. what time is this? Use a.m. or p.m.

Alex Ar [27]

7:15 AM

it is 15 minutes after 7 so 7:00 + 0:15 = 7:15
also breakfast is eaten in the morning so AM is right

6 0

2 years ago

Find the z-score such that the area under the standard normal curve to the left is 0.79.

Varvara68 [4.7K]

Answer:

Step-by-step explanation:

hope this helps

8 0

2 years ago