A line with a slope of -2 crosses the y-axis at (0, 3). The equation of the line is _______
2 answers:
In y = mx + b form, the slope is in the m position and the y int is in the b position
u have a slope of -2 and a y int of 3
so ur equation is : y = -2x + 3...but we need it in standard form
y = -2x + 3.....add 2x to both sides
2x + y = 3 <== ur equation
The point (0,3) is the y intercept of the line. y - intercelt is at y=3.
So we can use the slope intercept form of the straight line y = mx + b:-
y = -2x + 3
or
2x + y = 3
Its c).
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