For the absorbance of the solution in a 1.00 cm cell at 500 nm is mathematically given as
A’ = 0.16138
<h3>What is the absorbance of the solution in a 1.00 cm cell at 500 nm?</h3>
Absorbance (A) 2 – log (%T) = 2 – log (15.6) = 0.8069
Generally, the equation for the Beer’s law is mathematically given as
A = ε*c*l
0.8069 = ε*c*(5.00 )
ε*c = 0.16138 cm-1
then for when ε*c is constant
l’ = 1.00
A’ = (0.16138 cm-1)*(1.00 cm)
A’ = 0.16138
In conclusion, the absorbance of the solution in a 1.00 cm cell at 500 nm is
A’ = 0.16138
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brainly.com/question/3004869
The answer is D. Strong electrolytes
Strong electrolyte is a solute or solution that completely or almost completely dissociates when in solution. These are good conductors of electricity only when in molten/aqueous solution.
Strong electrolyte(aq) → Cation+(aq) + Anion−(aq)
Explanation:
2H2+O2------->2H2O
its yr balanced equation.
hope it helps
<h2>stay safe healthy and happy....</h2>
Answer:
Approximately 
(approximately 
.)
Explanation:
Calculate the quantity 
of lithium phosphate in 
of this
lithium phosphate solution.
.
Empirical formula of lithium phosphate: 
.
Look up the relative atomic mass of 
, 
,and 
on a modern periodic table:
Calculate the formula mass of :
.
Calculate the mass of that 
of formula units:
.
.
.
.