Answer:
207.19 is the cost on sale
Step-by-step explanation:
If there is a discount of 30%, we still have to pay 100-30 = 70%
295.99 * 70%
295.99 * .70
207.193
Rounding to the nearest cent
207.19 is the cost on sale
A system of equations is good for a problem like this.
Let x be the number of student tickets sold
Let y be the number of adult tickets sold
x + y = 200
2x + 3y = 490
x = 200 - y
2(200 - y) + 3y = 490
400 - 2y + 3y = 490
400 + y = 490
y = 90
The number of adult tickets sold was 90.
x + 90 = 200 --> x = 110
2x + 3(90) = 490 --> 2x + 270 = 490 --> 2x = 220 --> x = 110
The number student tickets sold was 110.
Answer:
Step-by-step explanation:
If parallel lines don't intersect, then there can't be any solutions. An intersection represents a solution.
If this is a true false question, the statement is false.
To make the inequality, we will use the ≥ sign to determine how many more tickets we will need. Before we write the inequality, let's see how much money was already made by the present tickets. 70 x 9.50 = $665.
We can write the inequality as $665 + $9.50t ≥ $1000 where t is the number of tickets sold. Now we can solve
$665 + $9.50t ≥ $1000, subtract 665
$9.50t ≥ $335. Now isolate the t by divide 9.50 to both sides
t ≥ 35.26 which we can round up to 36 because you cant sell 35.26 tickets.
So you need at least 36 more tickets to earn at least $1000
If you factor it then your answer will be -3(-3z-5) if you simplify the answer is 9z+15
