R(x) = 60x - 0.2x^2
The revenue is maximum when the derivative of R(x) = 0.
dR(x)/dx = 60 - 0.4x = 0
0.4x = 60
x = 60/0.4 = 150
Therefore, maximum revenue is 60(150) - 0.2(150)^2 = 9000 - 4500 = $4,500
Maximum revenue is $4,500 and the number of units is 150 units
Lateral area is the area of the faces, while surface area is the area of the faces and and bases.
Answer:
n = - 6
Step-by-step explanation:
Given k(x) then k(x) + n is a vertical translation of k(x)
• If n > 0 then a shift up of n units
• If n < 0 then a shift down of n units
Here k(x) has been shifted from (0, 0 ) to (0, - 6 )
That is a shift down of 6 units, then
p(x) = k(x) - 6
That is n = - 6
<h2>Solution (a) :-</h2>
Let the cost of the less expensive comic book be x .
Then :-
Using this equation , we can find the cost of the less expensive comic book .
Price of the less expensive book :-
Cost of the less expensive book is 107 .
Therefore , the epice of the less expensive book = $ 107 .
<h2>Solution (b) :-</h2>
Cost of the more expensive book = 11x
Which means :-
Therefore , the price of the more expensive book = $ 1177 .