The maximum value of the objective function is 330
<h3>How to maximize the
objective function?</h3>
The given parameters are:
Max w = 5y₁ + 3y₂
Subject to
y₁ + y₂ ≤ 50
2y₁ + 3y₂ ≤ 60
y₁ , y₂ ≥ 0
Start by plotting the graph of the constraints (see attachment)
From the attached graph, we have:
(y₁ , y₂) = (90, -40)
Substitute (y₁ , y₂) = (90, -40) in w = 5y₁ + 3y₂
w = 5 * 90 - 3 * 40
Evaluate
w = 330
Hence, the maximum value of the function is 330
Read more about objective functions at:
brainly.com/question/26036780
#SPJ1
2 hr and 45 minutes is = to 165min, so do 140 divided by 165, and you will get 0.8484miles per minute, which is D
Answer:
what rule my screen is white
Answer:
2×10¹² cells → 90 g
mass of 1 red blood cell : 90÷(2×10¹²) = 45×10^-12 g = 4.5×10^-11 g