Show that det(A) = 0 without directly evaluating the determinant. A = [-4 1 1 1 1; 1 -4 1 1 1; 1 1 -4 1 1; 1 1 1 -4 1; 1 1 1 1 -
4]
2 answers:
You could interpret them as system of equation and answer the question easily
from A
-4x + y + x + w =1
write in same form from A
as this system has five variables and four of them are unknowns it means the unique solution is not possible
So, det (A) = 0
Answer:You could interpret them as system of equation and answer the question easily
from A
-4x + y + x + w =1
write in same form from A
as this system has five variables and four of them are unknowns it means the unique solution is not possible
So, det (A) = 0
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