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2 years ago

10

John recieved a notice that his bank account was overdrawn by $40. He made a deposit and now his balance is $25. How much did Jo

hn deposit in his bank account?

2 answers:

Vitek1552 [10]2 years ago

8 0

He had to put $65 bc. he had to balance his account then added $25

charle [14.2K]2 years ago

6 0

Subtract 40 from 25 itvequals 15

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What is an equation of the line that passes through the points (6, -3) and<br> (-6, -5)?

SVETLANKA909090 [29]

Answer:

Step-by-step explanation:

The standard form of an equation for a straight line is y=mx+b, where m is the slope and b is the y-intercept (the value of y when x = 0).

We can calculate the slope from the two given points, (6,-3) and (-6,-5). Slope is Rise/Run, where Rise is the change in y and Run is the change in x.

From the two given points, starting at (-6,-5) and going to (6,-3):

Rise = (-3 - (-5)) = +2

Run = (6 - (-6)) = 12

Rise/Run (slope) = 2/12 or 1/6

The equation becomes y = (1/6)x + b

We can find b by enterieng either of the two given points and solving for b. I'll pick (6,-3):

y = (1/6)x + b

-3 = (1/6)*(6) + b

-3 = 1 + b [Now you can see why I chose (6,-3)]

b = -4

The equation is y = (1/6)x - 4

Check this with a DESMOS graph (attached).

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2 years ago

Three consecutive odd integers have a sum of 27. Find the integers.

jek_recluse [69]

$\sf \bf {\boxed {\mathbb {GIVEN:}}}$

Sum of three consecutive odd integers = $27$

$\sf \bf {\boxed {\mathbb {TO\:FIND:}}}$

The values of the three integers.

$\sf \bf {\boxed {\mathbb {SOLUTION:}}}$

$\sf\purple{The\:three\:consecutive \:odd\:integers\:are\:7,\:9\:and\:11.}$

$\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:\:EXPLANATION:}}}$

Let us assume the three consecutive odd integers to be $x$ , $(x+2)$ and $(x+4)$ .

As per the condition, we have

$Sum \: \: of \: \: the \: \: three \: \: consecutive \: \: odd \: \: integers = 27$

$➺ \: x + (x + 2) + (x + 4) = 27$

$➺ \: x + x + 2 + x + 4 = 27$

Now, collect the like terms.

$➺ \: (x + x + x) + (2 + 4) = 27$

$➺ \: 3x + 6 = 27$

$➺ \: 3x = 27 - 6$

$➺ \: 3x = 21$

$➺ \: x = \frac{21}{3} \\$

$➺ \: x = 7$

Therefore, the three consecutive odd integers whose sum is $27$ are $\boxed{ 7 }$ , $\boxed{ 9 }$ and $\boxed{ 11 }$ respectively.

$\sf \bf {\boxed {\mathbb {TO\:VERIFY :}}}$

$⇢ 7 + 9 + 11 = 27$

$⇢ 27 = 27$

⇢ L. H. S. = R. H. S.

$\sf\blue{Hence\:verified.}$

$\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35ヅ}}}}}$

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Answer:

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