Answer:
Step-by-step explanation:
Answer:
The value for partners savings bank at the end of 1 year is $12,362.70. The value for Selwyn's at the end of 1 year is $12,334.58. The future value obtained by investing in Partners Saving Bank is more as compared to Selwyn’s Saving Bank. Hence Joseph is recommended to choose Partners Saving Bank.
Step-by-step explanation:
Answer:
(23, 4)
Step-by-step explanation:
If we use substitution, we need to rewrite the 2nd equation so we can substitute it into the first.
Step 1: Rewrite 2nd equation
x = 5y + 3
Step 2: Substitution
2(5y + 3) - 5y = 26
Step 3: Distribute
10y + 6 - 5y = 26
Step 4: Combine like terms
5y + 6 = 26
Step 5: Isolate <em>y</em>
5y = 20
y = 4
Step 6: Find <em>x</em>
x - 5(4) = 3
x - 20 = 3
x = 23
And we have our final answer!
Answer:
- number of multiplies is n!
- n=10, 3.6 ms
- n=15, 21.8 min
- n=20, 77.09 yr
- n=25, 4.9×10^8 yr
Step-by-step explanation:
Expansion of a 2×2 determinant requires 2 multiplications. Expansion of an n×n determinant multiplies each of the n elements of a row or column by its (n-1)×(n-1) cofactor determinant. Then the number of multiplies is ...
mpy[n] = n·mp[n-1]
mpy[2] = 2
So, ...
mpy[n] = n! . . . n ≥ 2
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If each multiplication takes 1 nanosecond, then a 10×10 matrix requires ...
10! × 10^-9 s ≈ 0.0036288 s ≈ 0.004 s . . . for 10×10
Then the larger matrices take ...
n=15, 15! × 10^-9 ≈ 1307.67 s ≈ 21.8 min
n=20, 20! × 10^-9 ≈ 2.4329×10^9 s ≈ 77.09 years
n=25, 25! × 10^-9 ≈ 1.55112×10^16 s ≈ 4.915×10^8 years
_____
For the shorter time periods (less than 100 years), we use 365.25 days per year.
For the longer time periods (more than 400 years), we use 365.2425 days per year.
