Answer:
3.52176 x 10^-10 N
Explanation:
Fg = 3.52176 x 10^-10 Newton
Answer:
a = 2.22 [m/s^2]
Explanation:
First we have to convert from kilometers per hour to meters per second
![40 [\frac{km}{h}]*[\frac{1h}{3600s}]*[\frac{1000m}{1km}] = 11.11 [m/s]](https://tex.z-dn.net/?f=40%20%5B%5Cfrac%7Bkm%7D%7Bh%7D%5D%2A%5B%5Cfrac%7B1h%7D%7B3600s%7D%5D%2A%5B%5Cfrac%7B1000m%7D%7B1km%7D%5D%20%3D%2011.11%20%5Bm%2Fs%5D)
We have to use the following kinematics equation:
where:
Vf = final velocity = 11.11 [m/s]
Vi = initial velocity = 0
a = acceleration [m/s^2]
t = time = 5 [s]
The initial speed is taken as zero, as the car starts from zero.
11.11 = 0 + (a*5)
a = 2.22 [m/s^2]
Answer:
7 hours
Explanation:
The total charge contained in the battery is
And this is a charge, since it is a current multiplied by a time:
The current drawn by each headlight (which is the charge consumed per second) is
Since we have two headlight, the total current drawn is
Therefore, the total charge consumed by the two headlights each hour is
So, the time before the battery is dead is
The answer to this question lies in the definition of density. One material will just float over another if its density is smaller. If one material is denser than the other, it will sink.
Density can be defined as the mass per unit volume of a substance at a given pressure and temperature.
Thus, for a material to float in water, it does not depend on the weight, or rather on the mass, but on the distribution of the mass by the volume occupied, that is, of the density. The more distributed the mass, that is, the larger its volume, the less dense the object and it will float.
Object C has the lowest density<span>
65 N or 6.5 Kg ------------ 6 N or 6 Kg
This effective mass under water will be its actual mass minus the mass of the fluid displaced.
The buoyant force on a submerged object is equal to the weight of the fluid displaced.
Weight of object - buoyant force on object (the mass of the fluid displaced)
6Kg - 6.5Kg= - 0.5Kg
</span>Answer: C. object C
Answer:
A: They produce a real image.
Explanation:
The images formed on the retina of the eye for a normal visibility must always be real.
Only a real image can be physically projected on any physical object whereas the virtual images are visible due to reflections.
- The nearsightedness is corrected with the help of a concave lens since it is the condition of the eye lens remaining thick and curved to converge the rays entering the eyes after a shorter distance which results in their image formation even before the retinal surface so to initially diverge them a bit so that they converge on the retinal surface and form the image there we use concave lens. Vice-versa of the above justification in the case of farsightedness.
