Answer: It is only the 3rd equation that is a good example to Jeremy's argument. Others are counter examples to Jeremy's argument.
Step-by-step explanation:
Let us consider the general linear equation
Y = MX + C
On a coordinate plane, a line goes through points (0, negative 1) and (2, 0).
Slope = ( 0 - -1)/( 2- 0) = 1/2
When x = 0, Y = -1
Substitutes both into general linear equation
-1 = 1/2(0) + C
C = -1
The equations for the coordinate is therefore
Y = 1/2X - 1
Let's check the equations one after the other
y = negative one-half x minus 1
Y = -1/2X - 1
y = negative one-half x + 1
Y = -1/2X + 1
y = one-half x minus 1
Y = 1/2X - 1
y = one-half x + 1
Y = 1/2X + 1
It is only the 3rd equation that is a good example to Jeremy's argument. Others are counter examples to Jeremy's argument.
The slope of a horizontal line is always 0 as slope is rise over run . In the graph if you take any two points the y value is always 4 (1,4) and (2,4)
slope is 4-4/2-1=0/1 =0
Answer:
(x +5)
Step-by-step explanation:
The problem statement is telling you that one factor of (x⁴ +5x³ -3x -15) is (x³ -3). It is asking for the other factor. Clearly, you can find the other factor by dividing the polynomial by the given factor.
That is ...
(x⁴ +5x³ -3x -15) / (x³ -3) = (x +5)
so ...
(x⁴ +5x³ -3x -15) / (x +5) = (x³ -3)
The divisor of interest is (x +5).
20:10 | 2:1 | Hope this helps
0.84 repeating. Hope this helped.
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