Answer:
13 protons, 10 electrons, 14 neutrons
Explanation:
First, Al is having a charge of +3, and this means Al has lost 3 of its valence electrons.
Neutral atom of Al has atomic number of 13, but this isn't an atom. This is an ion which has lost 3 electrons, therefore the number of electrons becomes 10 while the number of protons remains 13.
We get the number of neutrons by subtracting the number of protons from the mass number. In this case, the mass number is 27 and proton number is 13. If you take away 13 from 27, you are left with 14. This is the number of neutrons.
Answer:
the new volume would be 1.62 L
Explanation:
stp is 0 degrees C or 273.15 K and 1atm for the pressure
22 degrees C is 295.15 K
use the combined gas law formula and solve for v2
v2=p1(v1)(t2)/p2(t1)
v2=1atm(1.2L)(295.15)/0.8atm(273.15K)
v2=1.62
Answer:
neutralization reaction
Explanation: Because Neutralization Reactions. ... from a neutralization reaction
Answer:
1.
2. a. No effect;
b. Products;
c. Products;
d. Reactants
Explanation:
1. Equilibrium constant might be written using standard guidelines:
- only aqueous species and gases are included in the equilibrium constant excluding solids and liquids;
- the constant involves two parts: in the numerator of a fraction we include the product of the concentrations of products;
- the denominator includes the product of the concentrations of reactants;
- the concentrations are raised to the power of the coefficients in the balanced chemical equation.
Based on the guidelines, we have two ions on the product side, a solid on the left side. Thus, the equilibrium constant has the following expression:
2. a. In the following problems, we'll be considering the common ion effect. According to the principle of Le Chatelier, an increase in concentration of any of the ions would shift the equilibrium towards the formation of our precipitate.
In this problem, we're adding calcium carbonate. It is insoluble, so it wouldn't have any effect on the equilibrium.
b. Sodium carbonate is completely soluble, it would release carbonate ions. The carbonate ions would combine with calcium cations and more precipitate would dissolve. This would shift the equilibrium towards formation of the products to reproduce the amount of calcium cations.
c. HCl would neutralize calcium hydroxide to produce calcium chloride and water, so the amount of calcium ions would increase, therefore, the products are favored.
d. NaOH contains hydroxide anions, so we'd have a common ion. An increase in hydroxide would produce more precipitate, so our reactants are favored.
I would personally say a Controlled Variable because you are purposefully not spraying the other arm.