For 10x² + 6 = 0, c= 6, a = _ _, and b = (Type integers or decimals.)
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The rate of change is 16.8 million tons per year
<em><u>Solution:</u></em>
Given that, the world catch of fish in 1950 was 12 million tons and in 1955 it was 96 million tons
<em><u>The average rate of change is given by formula:</u></em>
Value in 1950 = 12 million tons
Value in 1955 = 96 million tons
Change in value = value in 1955 - value in 1950
Change in value = 96 million - 12 million = 84 million tons
Number of years = 1950 to 1955 = 5 years
<em><u>Substitute the given values in formula,</u></em>
<em><u></u></em><em><u></u></em>
Thus rate of change is 16.8 million tons per year