Answer:
x = number of tickets sold for $26 = 3900 tickets
y = number of tickets sold for $40 = 2100 tickets
Step-by-step explanation:
A 6000-seat theater has tickets for sale at $26 and $40. How many tickets should be sold at each price for a sellout performance to generate a total revenue of $185,400?
Let
x = number of tickets sold for $26
y = number of tickets sold for $40
x + y = 6000
x = 6000 - y
$26 × x + $40 × y= $185, 400
26x + 40y = 185400
Substitute
26(6000 - y) + 40y = 185400
156000 - 26y + 40y = 185400
Collect like terms
- 26y + 40y = 185400 - 156000
14y = 29400
y = 29400/14
y = 2100 tickets
x = 6000 - y
x = 6000 - 2100
x = 3900 tickets
Hence
x = number of tickets sold for $26 = 3900 tickets
y = number of tickets sold for $40 = 2100 tickets
X + 3 = 9-4
First simplify the right side.
9-4 = 5
Now you have x + 3 = 5
Now subtract 3 from both sides:
X = 2
Answer: x = 2
Answer:
1/13
Step-by-step explanation:
y is proportional to x ⇒ y = kx
Plug in (26,2) and solve for k:
2 = k·26
k = 2/26 = 1/13
2.6925 is the mean/ avg you add all the numbers and divide by the amount of numbers you added
Answer:
635 (635.0293 not rounded)