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2 years ago

10

There are 3 ruby throated hummingbirds and two of another type at the feeder. The birds have a mass of 23 grams in all. What oth

er type of hummingbird is at the feeder? Explain

1 answer:

frutty [35]2 years ago

7 0

You have to divide by 23/3 which goes to 7. Which is 21. 2 ruby are left to feed.

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2 years ago

What’s a multi step equation that equals 22, 23, 29? please this is urgent

Delicious77 [7]

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6 1/2−7/8÷5 11/16<br> Help

Zanzabum

Answer:

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Step-by-step explanation:

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2 years ago

Calculate the average (arithmetic mean) of the list of numbers shown in the table. (rounded to the nearest tenth) A) 35.2 B) 39.

jenyasd209 [6]

<h3><u>Given Numbers:-</u></h3>

23, 33 ,33 ,27 ,25 ,68 ,27 ,44 ,72

<h3><u>To Find:-</u></h3>

average of this set of numbers

<h3><u>Solution</u>:-</h3>

$\green{ \underline { \boxed{ \sf{Average = \frac{Sum \:of \: observation}{Number \:of \: observation}}}}}$

$\longrightarrow$ Here, no of observation are 9

Now,

$\begin{gathered}\implies \small \sf Average =\frac{23+33+33+27+25+68+27+44+72}{9}\\\end{gathered}$

$\begin{gathered}\\\implies \small \sf Average =\frac{56+60+93+71+72}{9}\\\end{gathered}$

$\begin{gathered}\\\implies \sf Average =\frac{116+164+72}{9}\\\end{gathered}$

$\begin{gathered}\\\implies \sf Average =\frac{352}{9}\\\end{gathered}$

$\begin{gathered}\\\implies \sf Average = 39.1 \\\end{gathered}$

$\longrightarrow$ The Average of given set of numbers is 39.1 .

∴ Option C) is correct ✔️

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1 year ago

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