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2 years ago

What is the absolute value of -100000000000000?

Mathematics

2 answers:

Llana [10]2 years ago

6 0

|-100000000000000|=100000000000000

kozerog [31]2 years ago

3 0

Answer:

100000000000000

Step-by-step explanation:

because its the idtance from 0

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A box contains 24 transistors,4 of which are defective. If 4 are sold at random,find the following probabilities. i. Exactly 2 a

zavuch27 [327]

SOLUTION

This is a binomial probability. For i, we will apply the Binomial probability formula

i. Exactly 2 are defective

Using the formula, we have

$\begin{gathered} P_x=^nC_x\left(p^x\right?\left(q^{n-x}\right) \\ Where\text{ } \\ P_x=binomial\text{ probability} \\ x=number\text{ of times for a specific outcome with n trials =2} \\ p=\text{ probability of success = }\frac{4}{24}=\frac{1}{6} \\ q=probability\text{ of failure =1-}\frac{1}{6}=\frac{5}{6} \\ ^nC_x=\text{ number of combinations = }^4C_2 \\ n=\text{ number of trials = 4} \end{gathered}$

Note that I made the probability of being defective as the probability of success = p

and probability of none defective as probability of failure = q

Exactly 2 are defective becomes the binomial probability

$\begin{gathered} P_x=^4C_2\times\lparen\frac{1}{6})^2\times\lparen\frac{5}{6})^{4-2} \\ P_x=6\times\frac{1}{36}\times\frac{25}{36} \\ P_x=\frac{25}{216} \\ =0.1157 \end{gathered}$

Hence the answer is 0.1157

(ii) None is defective becomes

$\begin{gathered} \lparen\frac{5}{6})^4=\frac{625}{1296} \\ =0.4823 \end{gathered}$

hence the answer is 0.4823

(iii) All are defective

$\begin{gathered} \lparen\frac{1}{6})^4=\frac{1}{1296} \\ =0.00077 \end{gathered}$

(iv) At least one is defective

This is 1 - probability that none is defective

$\begin{gathered} 1-\lparen\frac{5}{6})^4 \\ =1-\frac{625}{1296} \\ =\frac{671}{1296} \\ =0.5177 \end{gathered}$

Hence the answer is 0.5177

3 0

3 months ago

Is the following statement true? Explain.

sukhopar [10]

Step-by-step explanation:

We can prove the statement is false by proof of contradiction:

We know that cos0° = 1 and cos90° = 0.

Let A = 0° and B = 90°.

Left-Hand Side:

cos(A + B) = cos(0° + 90°) = cos90° = 0.

Right-Hand Side:

cos(A) + cos(B) = cos(0°) + cos(90°)

= 1 + 0 = 1.

Since LHS =/= RHS, by proof of contradiction,

the statement is false.

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2 years ago

List the base-5 numbers of the decimals 16 to 32.

zhenek [66]

18 20 22 24 26 28 30

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2 years ago

Can someone help me I’ll give u 20 points

mamaluj [8]

Answer:

#1. X=3 and #2. Y=9

Step-by-step explanation:

Glad i could help, give me a follow, so if you need help with any other question, im here.

3 0

2 years ago

Read 2 more answers

The two spinners below are spun. Find the probability of spinning a 4 and a C.

r-ruslan [8.4K]

Step-by-step explanation:

S = { 1, 2, 3, 4, 5, 6 7, 8 }

n ( S ) = 8

Let A be the event of getting 4,

A = { 4 }

n ( A ) = 1

P ( A )

= n ( A ) / n ( S )

= 1 / 8

Therefore, the probability of spinning a 4 is 1 / 8.

S = { A, B, A, C, A, B }

n ( S ) = 6

Let Y be the event of getting C,

Y = { C }

n ( Y ) = 1

P ( Y )

= n ( Y ) / n ( S )

= 1 / 6

Therefore, the probability of spinning a C is 1 / 6.

3 0

2 years ago