Lagrangian:
where the function we want to minimize is actually
, but it's easy to see that
and
have critical points at the same vector
.
Derivatives of the Lagrangian set equal to zero:
Substituting the first three equations into the fourth gives
Solving for
, we get a single critical point at
, which in turn gives the least distance between the plane and (0, 2, 5) of
.
Answer:
Following are the responses to the given question:
Step-by-step explanation:
When x is squared, it's going to be bigger by the conclusion because the larger the faster. consistently exceeds , regardless of the price of X.
5x+3 is always 3 more so than 5x.
In particular, this can be classified according to its pathways
So can alternatively just say "eventually," which means because when x really is big, you need to find one another's values. Then just select x=100, then plug it into every single other. To confirm this order:
So, the ascending order must be the right order!
X=1 is the answer hope this helps
Answer:
[ext]T(x) = 2C / Speed[/ext]
Step-by-step explanation:
[ext]Time taken for the Ranger to get to the car = Sum total time taken to travel in the forest and on the road[/ext]
Since [ext]distance of the Ranger to the car = C[/ext]
[ext]Time taken = distance/speed[/ext]
[ext]Total Time taken T(x) = 2 * C / speed[/ext]
T(x) = 2C / speed
Answer:
D. Neither
Step-by-step explanation: