x^6 + 10ax^3 + 2ax^3 + 20a^2
(x^3 + 10a)(x^3 + 2a)
answer: (x^3 + 10a)(x^3 + 2a)
Hope it helps :)
Step-by-step explanation: In this problem, we're asked to state the domain and range for the following relation.
First of all, a relation is just a set of ordered pairs like you see in this problem. The domain is the set of all x-coordinates for those ordered pairs. So in this case the domain or D is {2, 5, -1, 0, -3}.
The range is the set of all y-coordinates for those ordered pairs. So in this case our range or R is {4, 3, -4, 9, 1}.
As you can see, angle 5 and angle 6 are supplementary. And angle 5 and angle 3 are congruent because they are alternate interior angles.
So it will be
x+2 = 180- x+3
move x over from the right to the left
2x+2 = 183
move 2 over from the left to the right
2x = 181
divide by 2
x= 90.5
and angle 3 and angle 1 are vertical angles so they are congruent. Using the angle 3 formula to solve for the answer:
90.5+3 =93.5
When angles are congruent, their measures are congruent, therefore, measure of angle 1 is 93.5
<span>(u-9)6
= 6u - 54 ...expanded by using distributive property
hope that helps</span>
