Find the equation of a line that passes the points (5, -9) and (0, -3)
2 answers:
Answer:
Y=-6/5x-3
Step-by-step explanation:
<em>Lets convert these two points into slope-intercept form.</em>
We can find the slope with the equation y2-y1/x2-x1=slope.
Insert the values into the equation.
-9-(-3)/5-0=slope
Simplify both sides.
-6/5=slope
The slope is -6/5. To complete equation, we need to find the y intercept.
The y intercept is -3. We know this because x is equal to 0 in this point.
Write it as an equation.
y=(-6/5)x+(-3)
Simplify.
The equation would be y=-6/5x-3
Hope this helps!
Answer:
y = -6/5x - 3
Step-by-step explanation:
Point Slope Form: (y - y1) = m(x - x1)
<u>Step 1: Find Slope</u>
m =
m =
m =
m =
m =
<u>Step 2: Plug into Point Slope Form</u>
(y - (-3)) = -6/5(x - 0)
y + 3 - 3 = -6/5x - 3
y = -6/5x - 3
Answer: y = -6/5x - 3
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Step-by-step explanation:
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Step-by-step explanation:
Given
The attached triangle
Required
Find cos V
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In this case:
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and
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