Let L be length and W be width
The perimeter of a rectangle is 2W+2L=36
Thus 2W=36-2L, W=18-L
Area of a rectangle is WL=80
Thus (18-L)(L)=80
18L-L^2=80
L^2-18L+80=0
(L-8)(L-10)
Thus L can either be 8 or 10.
Because WL=80
If L is 8, then W=10
If L is 10, then W=8
So either way, the notebook is 8 by 10
Answer:
25 cm.
Step-by-step explanation:
If the hypotenuse is x cm long the 2 legs are x-5 and x-10 cm long.
So by the Pythagoras theorem:
x^2 = (x - 5)^2 + (x - 10)^2
x^2 = x^2 - 10x + 25 + x^2 - 20x + 100
x^2 - 30x + 125 = 0
(x - 5)(x - 25) = 0
x = 5, 25
We can discard x = 5 because that would make the lengths of the legs negative so the hypotenuse = 25 cm long.
Answer:
1: D
2: B
Step-by-step explanation:
Answer:
x < -3
Step-by-step explanation:
Step 1: Subtract 6 from both sides.
Step 2: Divide both sides by 4.
Therefore, the answer is x < -3.