2 years ago

Which inequality statement describes the two numbers on a number line?

Mathematics

2 answers:

agasfer [191]2 years ago

6 0

the correct answer would be

B) 6 < 16

denpristay [2]2 years ago

4 0

Answer: B)6 < 16

Step-by-step explanation:

A number 10 units to the left of 16 is 6.

16 − 10 = 6

You might be interested in

What is the decimal equivalent of an 11% increase

valentinak56 [21]

Answer:

0.11

Step-by-step explanation:

You would convert the percentage to a fraction. Since the % symbol means 'out of 100', you would put 11 over 100: 11/100.

Then you would convert the fraction to a decimal: 0.11.

An easier way could also be to take the percentage and move it two decimal places to the right.

Ex: 43% moved two decimal places to the right would be 0.43.

I hope this helps!

3 0

2 years ago

Which mixed number and improper fraction are represented by the point M on the number line?

artcher [175]

The correct answer would be C
Please mark as Brainiest

5 0

3 years ago

Read 2 more answers

a pitcher could hold two twelfths of a gallon of water. If Roger filled up nine pitchers, how much water would he have?

Ivenika [448]

2/12=1/6
(1/6)×9=9/6=1.5 gallons

5 0

3 years ago

A store has a large supply of Pepsi, Dr. Pepper, and Mountain Dew. a. How many ways can you purchase 12 sodas if you must have a

lianna [129]

Answer:

A. 2 ways 2x6 12 divided by 6 B. 1 way 12 divided by 5 which is 2 remainder 2

Step-by-step explanation:

3 0

2 years ago

Calculate the frequency in hertz of photons of light with energy of 8.10 × 10-19 J.

stira [4]

The Planck–Einstein relation $E=hv$ gives that E, the photon energy, is equal to h, Planck's constant, times <span>ν</span>, the frequency.

We can solve the equation in terms of frequency to get
$v= \dfrac{E}{h}$

We substitute our given energy, $8.10 \times 10^{-19} J$ , and Planck's constant, $6.626 \times 10^{-34} Js$ .

$v= \dfrac{8.10 \times 10^{-19} J}{6.626 \times 10^{-34} Js}=1.22 \times 10^{15} s^{-1}=1.22 \times 10^{15} Hz$

5 0

2 years ago