Answer:
A
Step-by-step explanation:
Refer to the picture above.
Explainations are written in the pic above.
if you add 4 to it then you would get 8
A.
h(x)=3*5ˣ; h(0)=3, h(1)=15: rate of change is (15-3)/1=12 (1st section)
h(2)=3*25=75, h(3)=3*125=375: rate of change (375-75)/1=300 (2nd section)
b.
So the second section is 300/12=25 times greater than the first section.
The function is exponential and as x gets larger the difference between consecutive values of h(x) increases dramatically so the rate of change increases.
The initial investment = $250
<span>annual simple interest rate of 3% = 0.03
</span>
Let the number of years = n
the annual increase = 0.03 * 250
At the beginning of year 1 ⇒ n = 1 ⇒⇒⇒ A(1) = 250 + 0 * 250 * 0.03 = 250
At the beginning of year 2 ⇒ n = 2 ⇒⇒⇒ A(2) = 250 + 1 * 250 * 0.03
At the beginning of year 3 ⇒ n = 3 ⇒⇒⇒ A(2) = 250 + 2 * 250 * 0.03
and so on .......
∴ <span>The formula that can be used to find the account’s balance at the beginning of year n is:
</span>
A(n) = 250 + (n-1)(0.03 • 250)
<span>At the beginning of year 14 ⇒ n = 14 ⇒ substitute with n at A(n)</span>
∴ A(14) = 250 + (14-1)(0.03*250) = 347.5
So, the correct option is <span>D.A(n) = 250 + (n – 1)(0.03 • 250); $347.50
</span>
15% of 80 is 12.
To check this, you can multiply 80 x 0.15, which gives you an answer of 12.
