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2 years ago

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Need help on number 1, 5 and 7

1 answer:

zimovet [89]2 years ago

4 0

Answer:

1) y = (x + 8)² + 7; 5) y = (x - 6)² + 10; 7) y = (x - 3)² - 4

Step-by-step explanation:

Complete the square in order to figure these out. To complete the square, use the formula <em>[½B]</em><em>²</em><em>.</em><em> </em>Each time you do this, you get a perfect trinomial in the form of a product of two monomials [<em>h</em>], then you have to figure out how much more to deduct from or add on to your <em>C</em><em> </em>they gave you in each exercise [<em>k</em>].

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2 years ago

The sum of three consecutive odd integers is 69. find the integers

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Let the integers be x-2, x, x+2.

Given,

x -2 + x + x + 2 = 69

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Hence, the integers are 21, 23 and 25.

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2 years ago

Answer as many as you can please (write in slope-intercept form)

RoseWind [281]

Answer: See below

Step-by-step explanation:

For the first one, we are already given our slope. All we need to do is find the y-intercept, b.

y=-2x+b

6=-2(-3)+b

6=6+b

b=0

The slope-intercept form is y=-2x.

For the second one, we need to first find the slope using $m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$ .

$m=\frac{1-13}{3-(-6)} =\frac{-12}{9}$

Now that we have our slope, we can plug it into our slope-intercept form to solve for b.

$y=-\frac{12}{9} x+b$

$3=-\frac{12}{9}(1)+b$

$-\frac{9}{4} =b$

The slope-intercept form is $y=-\frac{12}{9} -\frac{9}{4}$ .

For the third one, we are already given the slope, so all we have to do is find b.

$y=-\frac{1}{2}x +b$

$-7=-\frac{1}{2} (-4)+b$

$-7=2+b$

$-9=b$

The slope-intercept form is $y=-\frac{1}{2} x-9$ .

For the last one, we need to first find the slope using $m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$ .

$m=\frac{-8-2}{3-1}=\frac{-10}{2} =-5$

Now that we have our slope, we can plug it into our slope-intercept form and find b.

$y=-5x+b$

$2=-5(1)+b$

$2=-5+b$

$7=b$

Our slope-intercept form is $y=-5x+7$ .

4 0

2 years ago