Complete question:
ΔU for a van der Waals gas increases by 475 J in an expansion process, and the magnitude of w is 93.0 J. calculate the magnitude of q for the process.
Answer:
The magnitude of q for the process 568 J.
Explanation:
Given;
change in internal energy of the gas, ΔU = 475 J
work done by the gas, w = 93 J
heat added to the system, = q
During gas expansion process, heat is added to the gas.
Apply the first law of thermodynamic to determine the magnitude of heat added to the gas.
ΔU = q - w
q = ΔU + w
q = 475 J + 93 J
q = 568 J
Therefore, the magnitude of q for the process 568 J.
Conservation, because you are conserving natural resources(water) and reusing aluminum cans which help the environment. Hope this helps!
Answer:
Explanation:
First of all we need to calculate the heat that the water in the cooler is able to release:
Where:
- Cp is the mass heat capacity of water
- V is the volume
is the density
To calculate the mass of CO2 that sublimes:
Knowing that the enthalpy of sublimation for the CO2 is: 
Answer:
1. Watt stream engine
2. McCormick reaper
3. Fulton steamboat
These are the correct answers.
Have A good day!! :)
