A solution must have both a solute and a solvent, and they must exist in solution together. the solute must be dissolved in the solvent; salt does not dissolve in a sugar bowl, nor does oil dissolve in water; it is a non polar molecule. we know that sugar (the solute) when added to water(solvent) will dissolve, creating a solution.
therefore, B
Answer:
1s2 2s2 2p2
Explanation:
it has 6 electrons in two energy levels so the sub levels are 1s, 2s and 2p
Arietis, camelopardalis, lyncis, scorpii, cancri, canis minoris
The answer is both B and C
positive chromic acid test is indicated by disappearance of orange colour from chromic ions and appearance of blue-green color from Chromium (iii) ion (reduction of chromium ion from CrO4 - to Cr3+)
positive chromic test indicated functional groups that can be oxidized.
cyclohexanol can be oxidized to become cyclohexanone
and pentan-3-ol can be oxidized to become pentan-3-one
hence both B and C will show positive chromic acid test
A) tert butanol although contains alcohol functional group, cannot be further oxidized as it is a tertiary alcohol
<span>Answer:
Nothing is balanced in your final equation: not H, not O, not Cr, not I and your charges aren't either.
Start with your 2 half reactions:
I- --> IO3-
Cr2O72- --> 2 Cr3+
Balance O by adding H2O:
I- + 3 H2O --> IO3-
Cr2O72- --> 2 Cr3+ + 7H2O
Balance H by adding H+:
I- + 3 H2O --> IO3- + 6 H+
Cr2O72- + 14 H+ --> 2 Cr3+ + 7H2O
Balance charge by adding e-:
I- + 3 H2O --> IO3- + 6 H+ + 6 e-
Cr2O72- + 14 H+ + 6 e- --> 2 Cr3+ + 7H2O
Since the numbers of electrons in your two half reactions are the same, just add them and simplify to give:
Cr2O72- + I- + 8 H+ --> IO3- + 2 Cr3+ + 4 H2O</span>
