The solution to the problem is as follows:
The quotient rule is ( f'(x)g(x)-f(x)g'(x) )/ (g(x))^2 {complex written on 1 line I know}
let f(x)=9x +13 and g(x)=2x+4
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f'(x)=9 and g'(x)=2 </span>
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therefore just substitute the equations in. </span>
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y'= 6x - ((9(2x+4)-2(9x+13))/((2x+4)^2))
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-30, 10*4=40 so you do 9-40+1 which is equal to -30
Answer:
Step-by-step explanation:
Since none of the answer choices match the drawing of the gardener, we assume the question is referring to the drawing of the partner.
The gardener's drawing is 1/4 of actual size. So, in terms of the gardener's drawing, actual size is ...
gardener's drawing = (1/4)actual size
actual size = 4(gardener's drawing)
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The partner's drawing is 1/20 of actual size, so is ...
partner's drawing = actual size/20 = (4(gardener's drawing))/20
partner's drawing = (4/20)(gardener's drawing)
partner's drawing = (gardener's drawing)/5
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Then the {length, width} of the partner's drawing are ...
partner's drawing {length, width} = {15 in, 10 in}/5 = {3 in, 2 in}
The partner's drawing has a length of 3 inches and a width of 2 inches.