a coin press creates a pressure of 3.20*10^8 Pa on a nickel of radius 0.0106 m. how much force does the press exert on the coin?
1 answer:
Answer:
1.13 x 10⁵N
Explanation:
Given parameters:
Pressure of the coin press = 3.2 x 10⁸ Pa
radius of the nickel coin = 0.0106m
Unknown:
Force of the press on coil = ?
Solution:
Our knowledge of pressure will help us solve this problem.
Pressure is defined as the force applied per unit area on a body.
Pressure =
Force = Pressure x Area
Since the pressure is known;
Area of the coin = Area of a circle = π r²
where r is the radius of the coin;
Area of the coin = π x 0.0106² = 3.53 x 10⁻⁴m²
Force = 3.2 x 10⁸ x 3.53 x 10⁻⁴ = 1.13 x 10⁵N
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Answer:
λ = 5.85 x 10⁻⁷ m = 585 nm
f = 5.13 x 10¹⁴ Hz
Explanation:
We will use Young's Double Slit Experiment's Formula here:
where,
λ = wavelength = ?
Y = Fringe Spacing = 6.5 cm = 0.065 m
d = slit separation = 0.048 mm = 4.8 x 10⁻⁵ m
L = screen distance = 5 m
Therefore,
<u>λ = 5.85 x 10⁻⁷ m = 585 nm</u>
Now, the frequency can be given as:
where,
f = frequency = ?
c = speed of light = 3 x 10⁸ m/s
Therefore,
<u>f = 5.13 x 10¹⁴ Hz</u>