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2 years ago

Which dimensions can create only one unique triangle?

Mathematics

1 answer:

s2008m [1.1K]2 years ago

3 0

Answer:

<h2>The dimensions must all add up to 180°.</h2>

Step-by-step explanation:

For example;

Your triangles' angles are: 56, 77, and 47.

56 + 77 + 47 = 180

*You did not give me any values to solve for, but just since you didn't- I'v provided an example to assist you in doing it yourself. If you want me to solve your full equation please add the angles or 3 dimensions of the triangle.

<h3>I hope this helped!</h3>

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Monica has a 24-inch square frame. There are 4 equal sides. She paints 34 of one side of the frame blue.

goldfiish [28.3K]

Answer:

Step-by-step explanation:

Monica has a 24-inch square frame. There are 4 equal sides. She paints 34 of one side of the frame blue.

Assuming that Monica paints 3/4 of one side of the frame blue.

Given,

24-inch square frame.

As there are 4 equal sides, we have,

24 / 4 = 6 in²

Per fraction we have 6 in²

As given, Monica paints 3/4 of one side of the frame blue.

⇒ 3/4 × 6 = 9/2 in²

[ 9/2 in² ] / [ 24 in² ]

= 3 / (2 × 8)

= 3/16

3/16 fraction of the frame Monica paint blue.

4 0

2 years ago

At the same time of day, a tree and a flagpole cast shadows as shown below.

Hitman42 [59]

Answer:

16 feet

Step-by-step explanation:

Height of tree = $\frac{20}{15}$ × 12ft

= 16ft

3 0

2 years ago

Combine like terms in the expression below. 99x+4.11xy+24y+33y−12x+9.08

ale4655 [162]

Is the answer 157.19xy tell me if I'm right

6 0

2 years ago

Read 2 more answers

Help with this two column proof

ddd [48]

We're given LM = NO which will be used in substitution later.

By the segment addition postulate, we can write
LN = LM+MN
which basically says "glue LM and MN together to get LN". All three segments fall on the same line.

Now substitute or replace LM with NO. This works because LM = NO is given

So we go from this
LN = LM+MN
to this
LN = NO+MN

Rearrange terms to go from
LN = NO+MN
to
LN = MN+NO
The formal property used is the "Commutative Property of Addition"

Now notice on the right hand side we can combine MN and NO to get MO. Again this is using the segment addition postulate.

So the last step is going from
LN = MN+NO
to
LN = MO

Have a look at the attached image to see how to format this proof into a two-column proof.

3 0

2 years ago

Prove that the max and min values of asinX + bcosX are respectively sqrt.(a^2+b^2) and -sqrt(a^2+b^2) .

strojnjashka [21]

The solution to the problem is as follows:
let y = asinx + bcosx

dy/dx = acosx - bsinx 

= 0 for max/min 

bsinx = acosx 

sinx/cosx = a/b 

tanx = a/b 

then the hypotenuse of the corresponding right-angled triangle is √(a^2 + b^2) 

the max/min of y occurs when tanx = a/b 

then sinx = a/√(a^2 + b^2) and cosx = b/√(a^2 + b^2) 

y = a( a/√(a^2 + b^2)) + b( b/√(a^2 + b^2)) 

= (a^2 + b^2)/√(a^2 + b^2) 

= √(a^2 + b^2)

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

6 0

2 years ago