Answer:
(c) no different than on a low-pressure day.
Explanation:
The force acting on the ship when it floats in water is the buoyant force. According to the Archimedes' principle: The magnitude of buoyant force acting on the body of the object is equal to the volume displaced by the object.
Thus, Buoyant forces are a volume phenomenon and is determined by the volume of the fluid displaced.
<u>Whether it is a high pressure day or a low pressure day, the level of the floating ship is unaffected because the increased or decreased pressure at the all the points of the water and the ship and there will be no change in the volume of the water displaced by the ship.</u>
Answer:
51.85m/s
Explanation:
Given parameters:
Mass of ball = 0.0459kg
Force = 2380N
Time taken = 0.001s
Unknown:
Speed of the ball afterwards = ?
Solution:
To solve this problem, we use Newton's second law of motion:
F = m x 
F is the force
m is the mass
v is the final velocity
u is the initial velocity
t is the time taken
2380 = 0.0459 x 
0.0459v = 2.38
v = 51.85m/s
Answer:
D. Uranium
Explanation:
I just got the answer right on my quiz.
Answer:
Explanation:
Let the radius of track required be r.
Centripetal force will be provided by frictional force which will be equal to
m v²/ r
Frictional force = mg x μ
So
m v² /r = mg μ
r = v² / μ g =
v = 29 km /h = 8.05 m /s
r =( 8.05 x 8.05 ) /( .32 x 9.8 ) = 20.66 m
Answer:
The object will rotate with constant angular acceleration
Explanation:
According to the Newton's Second Law for Whenever there is more than one torque acting on a rigid body that posses fixed axis, the moment of inertia as well as the angular acceleration is equals or proportional to the summation of the torques. It gives details on the relationship between rotational kinematics and torque as well as moment of inertia. This can be represented by the below equation.
∑iτi=Iα.
.Therefore when constant net torque is applied to object that is rotating, the object will rotate with constant angular acceleration
