Answer:
1. B) 5.7
2. A) 12
3. A) 11.4
4. A) 5.7
5. A) 16.2
6. A) 11.2
7. No, they do not form a right triangle
8. Yes, they do form a right triangle
Step-by-step explanation:
Extra tip: The hypotenuse has to be less than both sides added together, but cannot be more than either of the sides alone.
1.
16² + b² = 17²
256 + b² = 289
256 - 256 + b² = 289 - 256
b² = 33
√b² = √33
b = 5.74 or 5.7
2.
16² + b² = 20²
256 + b² = 400
256 - 256 + b² = 400 - 256
b² = 144
√b² = √144
b = 12
3.
7² + 9² = c²
49 + 81 = c²
130 = c²
√130 = √c²
11.40 or 11.4 = c
4.
7² + b² = 9²
49 + b² = 81
49 - 49 + b² = 81 - 49
b² = 32
√b² = √32
b = 5.65 or 5.7
5.
a² + 5² = 17²
a² + 25 = 289
a² + 25 - 25 = 289 - 25
a² = 264
√a² = √264
a = 16.24 or 16.2
6.
10² + b² = 15²
100 + b² = 225
100 - 100 + b² = 225 - 100
b² = 125
√b² = √125
b = 11.18 or 11.2
7.
15² + 8² = 16²
225 + 64 = 256
289 ≠ 256
8.
5² + 12² = 13²
25 + 144 = 169
169 = 169
4 (2x + 3) + 2 (x + 1) - 7
8x + 12 + 2x + 2 - 7
10x + 7
10x = -7
10x/10 = -7/10
x = -7/10
hope this helps
Answer:
Step-by-step explanation:
The point of this question is to find out the point where two lines intersect. First we need to get the equation of those lines
Slope of line 1:
(Yb -Ya)/(Xb - Xa) =
(-10 - (-14))/(-1 - (-3)) =
4/2 =
2
Use that slope to find the Y-intercept of line 1
y = 2x + b
-14 = 2(-3) +b
-14 = -6 + b
-8 = b
Therefore Line 1 is:
y = 2x - 8
Slope of line 2
(11 - 13)/(-1 - (-3)) =
-2/2 =
-1
Y-intercept of line 2
y = -x + b
13 = -(-3) +b
13 = 3 + b
10 = b
Therefore line 2 is
y = -x + 10
Now we have 2 equations to solve for the coordinates x and y
y = 2x - 8
y = -x + 10
Substitute y out in one of the equations
2x - 8 = -x + 10
3x = 18
x = 6
Plug x into one of the equations
y = 2(6) - 8
y = 12 - 8
y = 4
Therefore the solution is:
x=6, y=4
9 it’s the only one single digit number and each number has a 2 digit number or higher
First, you must know these formula d(e^f(x) = f'(x)e^x dx, e^a+b=e^a.e^b, and d(sinx) = cosxdx, secx = 1/ cosx
(secx)dy/dx=e^(y+sinx), implies <span>dy/dx=cosx .e^(y+sinx), and then
</span>dy=cosx .e^(y+sinx).dx, integdy=integ(cosx .e^(y+sinx).dx, equivalent of
integdy=integ(cosx .e^y.e^sinx)dx, integdy=e^y.integ.(cosx e^sinx)dx, but we know that d(e^sinx) =cosx e^sinx dx,
so integ.d(e^sinx) =integ.cosx e^sinx dx,
and e^sinx + C=integ.cosx e^sinxdx
finally, integdy=e^y.integ.(cosx e^sinx)dx=e^2. (e^sinx) +C
the answer is
y = e^2. (e^sinx) +C, you can check this answer to calculate dy/dx