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2 years ago

Explain how you can use the basic moves of algebra to transform the equation 5x-3y=12 into 0=12-5x+3y

Mathematics

2 answers:

dsp732 years ago

8 0

Pemdas
u could also have 5x-3y-12=0 it'd be easier

ozzi2 years ago

3 0

Subtract 5x and add 3y from the left side so that it can be moved to the right side. This will allow you to solve and get the second equation.

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Nataly [62]

Answer:

a) volume = 321.55 in³

Step-by-step explanation:

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2 years ago

HELP ASAP DUE TODAY PLZ HELP Solve the equation for x. 17=5+23x

LenKa [72]

Answer:

x=12/23

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

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2 years ago

Which expression can be used to determine the length of segment AB? On a coordinate plane, triangle A B C has points (4, 3), (ne

JulijaS [17]

Answer:

StartRoot 2 squared + 6 squared EndRoot

Step-by-step explanation:

we have

A(4,3) and B(-2,1)

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

substitute the given values

$AB=\sqrt{(1-3)^{2}+(-2-4)^{2}}$

$AB=\sqrt{(-2)^{2}+(-6)^{2}}$

$AB=\sqrt{40}\ units$

therefore

StartRoot 2 squared + 6 squared EndRoot

7 0

2 years ago

Read 2 more answers

What simple interest rate would allow $6000 to grow to an amount of $14550 in 10 years?

Harman [31]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{ \: 14.25 \: \% \: }}}}}$

Step-by-step explanation:

Given,

Principal ( P ) = $ 6000

Amount ( A ) = $ 14550

Time ( T ) = 10 years

Rate ( R ) = ?

Finding the Interest

The sum of principal and interest is called an amount.

From the definition,

$\boxed{ \sf{Amount = \: Principal + Interest}}$

plug the values

⇒ $\sf{14550 = 6000 + Interest}$

Swap the sides of the equation

⇒ $\sf{6000 + Interest = 14550}$

Move 6000 to right hand side and change its sign

⇒ $\sf{Interest = 14550 - 6000}$

Subtract 6000 from 14550

⇒ $\sf{Interest = \: 8550 \: }$

Interest = $ 8550

Finding the rate 

${ \boxed{ \sf{Rate = \frac{Interest \times 100}{Principal \times Time}}}}$

plug the values

⇒ $\sf{ Rate = \frac{8550 \times 100}{6000 \times 10} }$

Calculate

⇒ $\sf{Rate = \frac{855000}{60000} }$

⇒ $\sf{Rate = 14.25 \: \% \: }$

Hope I helped!

Best regards!!

8 0

2 years ago

Use the vertical line test to determine whether or not the graph is a graph of a function. plz help

liq [111]

Answer:

pretty sure both are yes

4 0

2 years ago