$\bf ~~~~~~\textit{parabola vertex form}
\\\\
\begin{array}{llll}
\boxed{y=a(x- h)^2+ k}\\\\
x=a(y- k)^2+ h
\end{array}
\qquad\qquad
vertex~~(\stackrel{}{ h},\stackrel{}{ k})\\\\
-------------------------------\\\\
f(x)=1(x-\stackrel{h}{6})^2\stackrel{k}{-31}\qquad \qquad vertex~(6,-31)$

7 0

2 years ago

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Draw to full scale (a) the plan (b) the front elevation as viewed from X and (c) the side elevation

VLD [36.1K]

Answer:

Nice job dude

Step-by-step explanation:

8 0

2 years ago

Find the value of each variable using sine and cosine round your answers to the nearest tenth

Fudgin [204]

9514 1404 393

Answer:

r ≈ 19.0

s ≈ 17.7

Step-by-step explanation:

The relevant trig relations are ...

Sin = Opposite/Hypotenuse

Cos = Adjacent/Hypotenuse

So, you have ...

cos(43°) = r/26

r = 26·cos(43°) ≈ 19.0

sin(43°) = s/26

s = 26·sin(43°) ≈ 17.7

5 0

2 years ago

If arc lm = 20 ft, find the radius of N

lozanna [386]

Answer:

120 ft

Step-by-step explanation:

60/360 or 1/6 of circle = 20 ft

full circle = 20 x 6 = 120 ft

diameter = 120/3.14 = 38.22 ft

radius = 38.22/2 = 19.11 ft

5 0

2 years ago

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