Answer:
506.912 L
Explanation:
From the question given above, the following data were obtained:
Number of mole of O₂ = 22.63 moles
Volume of O₂ =?
Recall:
1 mole of a gas occupy 22.4 L at STP.
With the above information, we obtained the volume occupied by 22.63 moles of O₂ as follow:
1 mole of O₂ occupied 22.4 L at STP.
Therefore, 22.63 moles of O₂ will occupy = 22.63 × 22.4 = 506.912 L at STP.
Thus, 22.63 moles of O₂ is equivalent to 506.912 L.
Explanation:
The boiling point of liquid nitrogen, liquid argon, and liquid oxygen are -196°C, -186°C, and -183°C respectively. So, the correct order is nitrogen, argon, oxygen.
I think the correct answer from the choices listed above is option D. The correct mass of nitrogen would be 2.9 g. The mass is calculated by multiplying the density and the volume of the substance. The correct answer should have two significant figures since it is the least precise operation.
