Answer:
I = I₀ + M(L/2)²
Explanation:
Given that the moment of inertia of a thin uniform rod of mass M and length L about an Axis perpendicular to the rod through its Centre is I₀.
The parallel axis theorem for moment of inertia states that the moment of inertia of a body about an axis passing through the centre of mass is equal to the sum of the moment of inertia of the body about an axis passing through the centre of mass and the product of mass and the square of the distance between the two axes.
The moment of inertia of the body about an axis passing through the centre of mass is given to be I₀
The distance between the two axes is L/2 (total length of the rod divided by 2
From the parallel axis theorem we have
I = I₀ + M(L/2)²
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The correct answer is that the surface winds will get stronger.
Answer:
The magnitude of applied force,parallel to the incline is 575.38 N and parallel to the floor is 605 N.
Explanation:
Given:
Mass of the piano 
= 190 kg
Inclined angle 
= 18 degree
Considering gravity, 
= 9.8 
And
Using, 
and 
<em>FBD diagram is attached with all the force acting on the floor and and the inclined. </em>
We have to find the magnitude of forces,when the man pushes it parallel to the incline and to the floor.
a.
When the man pushes it parallel to the incline.
Balancing the forces as 
.
⇒ 
⇒ 
⇒ Here it is negative as the force is acting downward.
⇒ Plugging the values of mass and angle .
⇒ 
⇒ 
N
b.
When the force is parallel to the floor.
⇒ 
⇒ 
⇒ Plugging the values.
⇒ 
⇒ 
N
So,
The magnitude of applied force in inclined direction is 575.38 Newton and parallel to the floor is 605 N.
