One number: x
Its consecutive: x + 1
Product:
x(x+1)=121
x² + x - 121 = 0
Δ = 1² - 4.1.(-121)
Δ = 1+484
Δ = 485
As square root of 485 is not integer, do not exist two consecutive numbers with product of 121
I'm guessing the answer is B? I tried to isolate r and I got that result. Sorry if it's wrong!
Answer:
Step-by-step explanation:
3/4 divied by 15 = 1/20