Ask question

Ask question

All categories

2 years ago

7

In March 2007, Business Week reported that at the top 50 business schools, students studied an average of 14.6 hours. You wonder

whether the amount UMSL students study is different from this 14.6 hour benchmark. Set up the hypotheses used in this situation.

1 answer:

Rasek [7]2 years ago

5 0

Answer:

The hypotheses used in this situation

$H_0:\mu = 14.6$

$H_a:\mu \neq 14.6$

Step-by-step explanation:

We are given that Business Week reported that at the top 50 business schools, students studied an average of 14.6 hours.

Mean = $\mu = 14.6$

Claim : The amount UMSL students study is different from this 14.6 hour benchmark.

The hypotheses used in this situation

$H_0:\mu = 14.6$

$H_a:\mu \neq 14.6$

You might be interested in

Adding and subtracting unlike fractions in word functions

UkoKoshka [18]

Answer:

3/8 tablespoons

Step-by-step explanation:

When we add fractions, we have to make each fraction a common denominator.

So we get 1/4 into 2/8 and we have 1/8

So we add and get 3/8

8 0

2 years ago

vfiekz [6]

Answer:

30 students: $346.5

1 student: $11.55

Step-by-step explanation:

It would cost a total of $57.75 every 5 student so just multiply by 6 to get your amount for 30 students. Then divide by 30 to get the amount per student.

8 0

2 years ago

Brookwood High School is considering adding co-ed soccer to the sports program for the fall

Karo-lina-s [1.5K]

Answer:

B

Step-by-step explanation:

5 0

2 years ago

Which could be the area of one face of the rectangular prism?Check all that apply

Temka [501]

the area of the rectangle=length x width
area=11x6=66

3 0

2 years ago

Read 2 more answers

If f(x) is an exponential function where f(4.5) = 24 and f(14.5) = 54, then find

iren2701 [21]

Answer:

The value of $f(6.5)$ is 28.22.

Step-by-step explanation:

The exponential function is modelled after this model:

$y = A\cdot e^{B\cdot x}$ (1)

Where:

$A, B$ - Coefficients.

$x$ - Independent variable.

$y$ - Dependent variable.

By using all information from statement, we have the following system of equations: $(x_{1},y_{1}) = (4.5, 24)$ , $(x_{2}, y_{2}) = (14.5, 54)$

$A\cdot e^{4.5\cdot B} = 24$ (2)

$A\cdot e^{14.5\cdot B} = 54$ (3)

By dividing (3) by (2), we calculate $B$ :

$e^{10\cdot B} = \frac{9}{4}$

$10\cdot B = \ln \frac{9}{4}$

$B = \frac{1}{10}\cdot \ln \frac{9}{4}$

$B \approx 0.081$

If we know that $(x,y) = (4.5, 24)$ and $B \approx 0.081$ , then the value of $A$ is:

$A = \frac{y}{e^{B\cdot x }}$

$A \approx 16.669$

If we know that $x = 6.5$ , then the value of $y$ is:

$y = 16.669\cdot e^{0.081\cdot x}$ (4)

$y \approx 28.221$

The value of $f(6.5)$ is 28.22.

6 0

2 years ago