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3 years ago

5

I you were flipping a nickel a dime and a quarter how many possible outcomes are possible for getting heads or tails

1 answer:

zhuklara [117]3 years ago

8 0

3/6 possible out comes for heads and tails

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Monica has 5 red cubes, 6 blue cubes, and 4 green cubes in a bag. She randomly chooses 9 cubes and gets 3 of each color.

aleksandrvk [35]

Red blue green so 3

7 0

2 years ago

In two or three sentences explain how you would solve for the real solutions of the following equation: please help asap!!

g100num [7]

the real solutions for the equation $x^{3}=-64$ are -

$x=4,2+-2\sqrt{3i}$

Step-by-step explanation:

$x^{3}$ = $- 64$

$x^{3} +64$ = 0

We can write 64 as $4^{3}$

$x^{3}$ + $4^{3}$ = 0

using the identity ( $x^{3}+y^{3} = (x+y)(x^{2} -xy+y^{2} )$ )

we get,

= $(x+4) (x^{2} -x*4+4^{2} )$

= $(x+4)(x^{2} -4x+16)$ ....................(1)

solving the quadratic equation ,

$x^{2} -4x+16$ =0

solutions of this quadratic equation can be obtained by

$x=-b +- \sqrt{b^{2}-4ac } /2a$

let use y for factors

$x=-(-4x)+-\sqrt{(-4x^{2} )-4*x^{2} *16} / 2*x^{2}$

$x=4x+-\sqrt{16x^{2} -64x^{2} } /2x^{2}$

$x=4+-\sqrt{16-64}/2$

$x=4+-4\sqrt{3i} /2$

<u /> $x=2+-2\sqrt{3i}$ ..................(2)

from the equation 1 we have,

$x-4=0$

which gives solution $x=4$

and from equation 2 we got $x=2+-2\sqrt{3i}$

so the real solutions for the equation $x^{3}=-64$ are -

$x=4,2+-2\sqrt{3i}$

3 0

2 years ago

Un paese contava 12000 abitanti all'inizio del 2007 durante l'anno i nati sono 1,7 % del totale degli abitanti e morti sono 2% c

grandymaker [24]

Step-by-step explanation:

12000 abitanti all'inizio del 2007

nati: 1.7% × 12000 = 204

morti: 2% × 12000 = 240

popolazione all'inizio del 2008: 12000 + 204 - 240 = 11964

6 0

1 year ago

PLEASSSSSSEEEEEEEEE HELPPPPPPPPP !!!!!! Tyler begins funding a college education for his son. He saves $1000 the first year. Eac

vladimir2022 [97]

1050 each year he funds them

5 0

2 years ago

Read 2 more answers

How do I "undo" multiplication

Law Incorporation [45]

A way of undoing any operation, is using the inverse of the operation. So if you want to ‘undo’ addition you subtract, and if you want to ‘undo’ multiplication you divide.

Hope this helps!!

8 0

2 years ago

Read 2 more answers