We know that sin2x=2sinxcosx
(search the net for proof if you wish)
So the original equation becomes
2sinxcosx-sinx=0
The two terms both have sinx that can be taken out to get:
sinx(2cosx-1)=0
This is true if sinx=0 or 2cosx-1=0 , rewritten: cosx=1/2
sinx=0 than x=2kπ
cosx=1/2 than x=π/3+2kπ
where k is an integer
Answer:
(2x+9) ^3
Step-by-step explanation:
(((8 • (x3)) + 729) + (22•33x2)) + 486x
((23x3 + 729) + (22•33x2)) + 486x
Factoring: 8x3+108x2+486x+729
8x3+108x2+486x+729 is a perfect cube which means it is the cube of another polynomial
In our case, the cubic root of 8x3+108x2+486x+729 is 2x+9
Factorization is (2x+9)3
Hope this helped
If all were dimes, the value would be $3.30. Brendan has $2.85 more than that. Each quarter that replaces a dime increases the value by $0.15, so Brendan must have $2.85/$0.15 = 19 quarters.
Brendan has 14 dimes and 19 quarters.
Answer:
thanks for the points ily
Answer:
ok the anser is 39
Step-by-step explanation:
ypu do bacic equagens
